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5b^2-13b-27=0
a = 5; b = -13; c = -27;
Δ = b2-4ac
Δ = -132-4·5·(-27)
Δ = 709
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-13)-\sqrt{709}}{2*5}=\frac{13-\sqrt{709}}{10} $$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-13)+\sqrt{709}}{2*5}=\frac{13+\sqrt{709}}{10} $
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